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The mass of dinitrogen in grams produced...

The mass of dinitrogen in grams produced by the thermal decomposition of 2 moles of ammonium dichromate.

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To find the mass of dinitrogen (N₂) produced by the thermal decomposition of 2 moles of ammonium dichromate (NH₄)₂Cr₂O₇, we can follow these steps: ### Step 1: Write the balanced chemical equation for the thermal decomposition of ammonium dichromate. The balanced equation for the thermal decomposition of ammonium dichromate is: \[ 2 \, (NH_4)_2Cr_2O_7 \, \text{(s)} \rightarrow 2 \, N_2 \, \text{(g)} + 4 \, H_2O \, \text{(g)} + Cr_2O_3 \, \text{(s)} \] ### Step 2: Determine the amount of dinitrogen produced from 2 moles of ammonium dichromate. From the balanced equation, we can see that 2 moles of ammonium dichromate produce 2 moles of dinitrogen. Therefore, if we start with 2 moles of ammonium dichromate, we will produce: \[ 2 \, \text{moles of } N_2 \] ### Step 3: Calculate the mass of dinitrogen produced. To find the mass of dinitrogen produced, we need to use the molar mass of dinitrogen (N₂). The molar mass of nitrogen (N) is approximately 14 g/mol, so the molar mass of dinitrogen (N₂) is: \[ M(N_2) = 2 \times 14 \, \text{g/mol} = 28 \, \text{g/mol} \] Now, we can calculate the mass of 2 moles of dinitrogen: \[ \text{Mass of } N_2 = \text{Number of moles} \times \text{Molar mass} \] \[ \text{Mass of } N_2 = 2 \, \text{moles} \times 28 \, \text{g/mol} = 56 \, \text{g} \] ### Final Answer: The mass of dinitrogen produced by the thermal decomposition of 2 moles of ammonium dichromate is **56 grams**. ---

To find the mass of dinitrogen (N₂) produced by the thermal decomposition of 2 moles of ammonium dichromate (NH₄)₂Cr₂O₇, we can follow these steps: ### Step 1: Write the balanced chemical equation for the thermal decomposition of ammonium dichromate. The balanced equation for the thermal decomposition of ammonium dichromate is: \[ 2 \, (NH_4)_2Cr_2O_7 \, \text{(s)} \rightarrow 2 \, N_2 \, \text{(g)} + 4 \, H_2O \, \text{(g)} + Cr_2O_3 \, \text{(s)} \] ...
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