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If a conic passes through (1, 0) and sat...

If a conic passes through (1, 0) and satisfies differential equation `(1 + y^2) dx - xy dy = 0` . Then the foci is:

Text Solution

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`int(dx)/(x)=int(ydy)/(1+y^(2))`
`lnx=(1)/(2)ln(1+y^(2))+c`
Passes through (1, 0) so c = 0
`x^(2)=1+y^(2)`
`x^(2)-y^(2)=1 rarr " foci "rarr(pm sqrt2, 0)`
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