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sum(r=1)^(10)(r+{(r)/(7)}+{(2r)/(7)})= w...

`sum_(r=1)^(10)(r+{(r)/(7)}+{(2r)/(7)})=` where `{x} rarr` fractional part function

A

`(445)/(7)`

B

`(454)/(7)`

C

`(447)/(17)`

D

`(447)/(7)`

Text Solution

Verified by Experts

The correct Answer is:
A
`sum_(r=1)^(10) r+sum_(r=1)^(10){(r)/(7)} + sum_(r=1)^(10){(2r)/(7)}`

`= 55+(21+6)/(7) + (21+12)/(7) = 55+(27+33)/(7) = 55+(60)/(7)=(385+60)/(7) = (445)/(7)`
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