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A particle of mass m with an initial vel...

A particle of mass m with an initial velocity `u hati+2u hatj` collides with a particle of mass 3m at rest. After collision, the two particles stick together and the combined particle moves with a velocity `v hati+v' hatj`. Which of the following is incorrect?

A

`v=v'//2`

B

`v=2v'`

C

`v=u//4`

D

`v'=u//2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the principle of conservation of momentum. ### Step 1: Identify the initial momentum of the system The initial momentum of the system can be calculated using the formula: \[ \text{Initial Momentum} = \text{momentum of particle 1} + \text{momentum of particle 2} \] For the first particle (mass \( m \) with initial velocity \( u \hat{i} + 2u \hat{j} \)): \[ \text{Momentum of particle 1} = m \cdot (u \hat{i} + 2u \hat{j}) = m u \hat{i} + 2m u \hat{j} \] For the second particle (mass \( 3m \) at rest): \[ \text{Momentum of particle 2} = 3m \cdot 0 = 0 \] Thus, the total initial momentum is: \[ \text{Initial Momentum} = m u \hat{i} + 2m u \hat{j} + 0 = m u \hat{i} + 2m u \hat{j} \] ### Step 2: Identify the final momentum of the system After the collision, the two particles stick together, so the total mass becomes \( 4m \) and moves with a velocity \( v \hat{i} + v' \hat{j} \): \[ \text{Final Momentum} = \text{Total mass} \times \text{Velocity} = 4m (v \hat{i} + v' \hat{j}) = 4m v \hat{i} + 4m v' \hat{j} \] ### Step 3: Apply the conservation of momentum According to the conservation of momentum: \[ \text{Initial Momentum} = \text{Final Momentum} \] Thus, we can equate the two: \[ m u \hat{i} + 2m u \hat{j} = 4m v \hat{i} + 4m v' \hat{j} \] ### Step 4: Simplify the equation Dividing through by \( m \) (assuming \( m \neq 0 \)): \[ u \hat{i} + 2u \hat{j} = 4v \hat{i} + 4v' \hat{j} \] ### Step 5: Compare coefficients From the equation, we can compare the coefficients of \( \hat{i} \) and \( \hat{j} \): 1. For \( \hat{i} \): \[ u = 4v \] \[ v = \frac{u}{4} \] 2. For \( \hat{j} \): \[ 2u = 4v' \] \[ v' = \frac{u}{2} \] ### Step 6: Establish the relationship between \( v \) and \( v' \) From the equations derived: - \( v = \frac{u}{4} \) - \( v' = \frac{u}{2} \) Now, we can express \( v' \) in terms of \( v \): \[ v' = 2v \] ### Step 7: Identify the incorrect statement Now we need to check the statements provided: 1. \( v' = 2v \) (True) 2. \( v = \frac{u}{4} \) (True) 3. \( v' = \frac{u}{2} \) (True) 4. \( v = 2v' \) (False, as \( v' = 2v \)) Thus, the incorrect statement is: \[ v = 2v' \]

To solve the problem step by step, we will use the principle of conservation of momentum. ### Step 1: Identify the initial momentum of the system The initial momentum of the system can be calculated using the formula: \[ \text{Initial Momentum} = \text{momentum of particle 1} + \text{momentum of particle 2} \] For the first particle (mass \( m \) with initial velocity \( u \hat{i} + 2u \hat{j} \)): \[ \text{Momentum of particle 1} = m \cdot (u \hat{i} + 2u \hat{j}) = m u \hat{i} + 2m u \hat{j} \] ...
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