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Distance travelled by linear scale of sc...

Distance travelled by linear scale of screw gauge during two full rotation of circular scale is 1mm and circular scale has 50 divisions. In an experiment to measure thickness of a plate, six divisions of main scale are clearly visible and `28^(th)` division of circular scale coincides with reference line. Moreover when studs touch each other, zero of circular scale lies 4 division below the reference line, thickness of the plate will be:

A

3.28 mm

B

2.74 mm

C

3.32 mm

D

3.24 mm

Text Solution

Verified by Experts

The correct Answer is:
D
Pitch p = 0.5 mm
Device has +ve zero error
`R=6p+28(p)/(50)-4(p)/(50)=6p+(24p)/(50),3mm+(24)/(50)xx0.5=3.24mm`
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