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A block of mass 10 kg is placed on roug...

A block of mass 10 kg is placed on rough inclined plane of inclination angle `37^(@)` .Coefficient of friction between block & plane is `0*8`, find minimum magnitude of F so that block remains at rest .

Text Solution

Verified by Experts

The correct Answer is:
20
From free body diagram in vertical direction we can say
`N cos theta = mg + mu N sin theta`
`N = (mg)/(cos theta - mu sin theta) `
So, `a = (g sin theta)/(cos theta - mu sin theta) + (mu g cos theta)/(cos theta - mu sin theta)`
`= g [(sin theta + mu sin theta)/(cos theta - mu sin theta)] = 20 m//"sec"^2`.
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