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A gaseous mixture consists of 16 g of he...

A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio `C_p //C_V` of the mixture is :

A

`(23)/(29)`

B

`(47)/(23)`

C

`(29)/(23)`

D

`(47)/(29)`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(v"mix") = (n_(1)C_(v_(1)) + n_(2) C_(v_(2)))/(n_(1) + n_(2)) = ((4) ((3R)/(2)) + ((1)/(2)) ((5R)/(2)))/(4+ (1)/(2)) = (29R)/(18)`
`C_(p "mix") = (47R)/(18), " So" (C_(p))/(C_(v)) = (47)/(29)`
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