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Three particles of masses 0.5 kg, 1kg, 1...

Three particles of masses 0.5 kg, 1kg, 1.5 kg are placed at the three corners of a right angle triangle of sides 3,4,5 cm as shown in adjoining figure. What would be coordinates (x,y) of the center of mass of system?

A

The centre of mass is 2.8 cm to the right and 1.7 cm above the 0.50 kg particle

B

The centre of mass is 2.2 cm to the right and 1.8 cm above the 0.50 kg particle

C

The centre of mass is 2.1 cm to the right and 1.7 cm above the 0.50 kg particle

D

The centre of mass is 1.3 cm to the right and 1.5 cm above the 0.50 kg particle

Text Solution

Verified by Experts

The correct Answer is:
D
Take origin at 0.50 kg mass
y= Vertical, x=Horizontal
`x_(c.m)=(0.50(0)+1xx4+1.5xx(0))/(0.50+1+1.5)`
`x_(c.m)=(4)/(3)," "y_(c.m)=(0.50(0)+1(0)+1.5(3))/(0.50+1+1.5)`
`y_(c.m)=(4.5)/(3)," "y_(c.m)=1.5cm`
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