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A particle (m = 1kg) slides down a frict...

A particle (m = 1kg) slides down a frictionless track (AOC) starting from rest at a point A (height 2m). After reaching C, the particle continues to move freely in air as a projectile. When it reaches point C (height 1 m), the vertical speed of the particle (in m/s) is (Figure drawn is schematic and not to scale , take g = 9.8 m/`sec^(2)`) [Take ]

Text Solution

Verified by Experts

The correct Answer is:
2.23
`mgh_(A)=mgh_(c)+(1)/(2)mv^(2)`
`V=sqrt(2g(2-1))=v=2sqrt5=2xx2.3=4.46m//s`
`V_(y)=Vsin30^(@)`
`V_(y)=vsin30^(@)=4.46xx(1)/(2)=2.23m//s`
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