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A loop made of straight edges has six co...

A loop made of straight edges has six corners at A (0, 0, 0), B (L, 0, 0), C (L,L,0),D(0,L,0), E(0,L, L) and F (0, 0,L). A magnetic field `B=B_(0)(hat"I"+hatk)` T is present in the region. The flux passing through the loop ABCDEFA (in that order) is

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The correct Answer is:
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`vecA=vecA_(1)+vecA_(2)`
`vecA=(L^(2)hatk+L^(2)hati)`
`vecB=B_(0)(hati+hatk)T`
`phi=vecB.vecA`
`phi=B_(0)(hati+hatk).(L^(2)hatk+L^(2)hati)`
`phi=2B_(0)L^(2)Wb`
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