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Monochromatic light of wavelength 3000 Å...

Monochromatic light of wavelength 3000 Å is incident normally on a surface of area `4 cm^(2)` . If the intensity of the light is `15 xx 10^(-2) W//m^(2)` . The rate at which photons strike the surface is `K xx 10^(13)` photon/s. The value of K is _________.

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To solve the problem, we need to find the rate at which photons strike the surface, denoted as \( K \times 10^{13} \) photons/s. We will follow these steps: ### Step 1: Convert Wavelength to Meters The wavelength \( \lambda \) is given as 3000 Å (angstroms). We need to convert this to meters: \[ \lambda = 3000 \, \text{Å} = 3000 \times 10^{-10} \, \text{m} = 3.0 \times 10^{-7} \, \text{m} \] **Hint:** Remember that 1 Å = \( 10^{-10} \) m. ### Step 2: Calculate the Energy of One Photon The energy \( E \) of a single photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: - \( h = 6.626 \times 10^{-34} \, \text{J s} \) (Planck's constant) - \( c = 3.0 \times 10^{8} \, \text{m/s} \) (speed of light) Substituting the values: \[ E = \frac{(6.626 \times 10^{-34}) \times (3.0 \times 10^{8})}{3.0 \times 10^{-7}} \] Calculating this gives: \[ E = 6.626 \times 10^{-19} \, \text{J} \] **Hint:** Use the values of \( h \) and \( c \) carefully, and ensure units are consistent. ### Step 3: Calculate the Area in Square Meters The area \( A \) is given as \( 4 \, \text{cm}^2 \). We need to convert this to square meters: \[ A = 4 \, \text{cm}^2 = 4 \times 10^{-4} \, \text{m}^2 \] **Hint:** Remember that \( 1 \, \text{cm}^2 = 10^{-4} \, \text{m}^2 \). ### Step 4: Calculate the Power Incident on the Surface The intensity \( I \) is given as \( 15 \times 10^{-2} \, \text{W/m}^2 \). The power \( P \) incident on the surface can be calculated using: \[ P = I \times A \] Substituting the values: \[ P = (15 \times 10^{-2}) \times (4 \times 10^{-4}) = 6.0 \times 10^{-5} \, \text{W} \] **Hint:** Power is the product of intensity and area. ### Step 5: Calculate the Number of Photons Striking the Surface per Second The number of photons \( n \) striking the surface per second can be calculated using: \[ n = \frac{P}{E} \] Substituting the values: \[ n = \frac{6.0 \times 10^{-5}}{6.626 \times 10^{-19}} \approx 9.05 \times 10^{13} \, \text{photons/s} \] **Hint:** Make sure to divide the power by the energy of one photon to find the number of photons. ### Step 6: Determine the Value of \( K \) From the calculation, we have: \[ n \approx 9.05 \times 10^{13} \, \text{photons/s} = K \times 10^{13} \] Thus, \( K \) is: \[ K \approx 9.05 \] **Final Answer:** The value of \( K \) is approximately \( 9.05 \).

To solve the problem, we need to find the rate at which photons strike the surface, denoted as \( K \times 10^{13} \) photons/s. We will follow these steps: ### Step 1: Convert Wavelength to Meters The wavelength \( \lambda \) is given as 3000 Å (angstroms). We need to convert this to meters: \[ \lambda = 3000 \, \text{Å} = 3000 \times 10^{-10} \, \text{m} = 3.0 \times 10^{-7} \, \text{m} \] ...
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