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For the reaction, 2A (s) + 2B (g)to C (g...

For the reaction, `2A (s) + 2B (g)to C (g) + D(s) at 298K`
`Delta U ^(@) =-10.5KJ and Delta S ^(@)=-44.10 JK^(-1)`
Calculate `Delta G ^(@)` for the reaction (in Joules).

Text Solution

Verified by Experts

The correct Answer is:
164.8
`2A(s) = 2B(g) rarr C(g) + D(s)`
`Delta n_(g) = 1-2 = -1, " "Delta G^(@) = Delta H^(@) - T Delta S^(@), " "Delta H^(@) = Delta U^(@) + Delta n_(g)R T`
`Delta H^(@) = -10.5 kJ + (-1)(8.314) xx 10^(-3)kJ)(298K) = -10.5 - 2.48 = - 12.977 kJ`
`Delta G^(@) = Delta H^(@) - T Delta S^(@) = 12.977 kJ - 298 (-44.1 xx 10^(-3) kJ) = 0.1648 kJ = 164.8` Joules.
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