Home
Class 12
MATHS
If a circle of radius 3 units is touchin...

If a circle of radius `3` units is touching the lines `sqrt3y^2-4xy+ sqrt3x^2=0` in the first quadrant then the length of chord of contact to this circle, is:

A

`(sqrt3 +1)/(2)`

B

`(sqrt3+1)/(sqrt2)`

C

`3((sqrt3+1)/(sqrt2))`

D

`(3(sqrt3+1))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C


Given equation of lines `sqrt3 y^2 - 4xy +sqrt3 x^2 = 0`
`sqrt3 y^2 - 3xy - xy + sqrt3 x^2 = 0`
`rArr (sqrt3 y- x)(y-sqrt3 x) = 0 rArr y = (x)/(sqrt3) , y = sqrt3x`
`angle APO = 75^@`
Length of chord of contact AB
` = 2.3 sin 75^@ = 6(sin 45^@ cos 30^@ + sin 30^@ cos 45^@)`
`6((1)/(sqrt2) .(sqrt3)/(2) + 1/2 . (1)/(sqrt2)) = (6(sqrt3+1))/(2sqrt2) = (3(sqrt3 + 1))/(sqrt2)`
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 5

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • MOCK TEST 4

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • MOCK TEST 6

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

If a circle of radius r is touching the lines x^2-4x y+y^2=0 in the first quadrant at points Aa n dB , then the area of triangle O A B(O being the origin) is (a) 3sqrt(3)(r^2)/4 (b) (sqrt(3)r^2)/4 (c) (3r^2)/4 (d) r^2

A circle of radius 6 units touches the coordinates axes in the first quadrant. Find the equation of its image in the line mirror y=0.

A circle of radius 4 units touches the coordinate axes in the first quadrant. Find the equation of its images with respect to the line mirrors x=0\ a n d\ y=0.

If a circle whose center is (1,-3) touches the line 3x-4y-5=0 , then find its radius.

If a circle whose center is (1,-3) touches the line 3x-4y-5=0 , then find its radius.

Equation of the circle of radius sqrt(2) , and touching the line |x-1| =|y-1| , is :

Find the area bounded by the circle x^2 + y^2 = 16 and the line sqrt3y = x in the first quadrant, using integration.

Find the area bounded by the circle x^2 + y^2 = 16 and the line sqrt3y = x in the first quadrant, using integration.

Centre of a circle of radius 4sqrt(5) lies on the line y=x and satisfies the inequality 3x+6y > 10. If the line x+2y=3 is a tangent to the circle, then the equation of the circle is

Circles of radius 5 units intersects the circle (x-1)^(2)+(x-2)^(2)=9 in a such a way that the length of the common chord is of maximum length. If the slope of common chord is (3)/(4) , then find the centre of the circle.