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Solution of differential equation of (x+...

Solution of differential equation of `(x+2y^3)dy = ydx` is :

A

`x = y^3 = cy`

B

`y = x^3 = cx `

C

`x^2 = y^2 =cxy`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
The given differential equation can be written as
`(dx)/(dy) - 1/y. x = 2y^2`
I.F. `e^(-int 1/y dy) = 1/y`
So solution is `x. 1/y = int 1/y 2y^2 .""dy= y^2+c`
So `x= y^3 + cy`
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