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Find the equation of the tangent to the ...

Find the equation of the tangent to the circle `x^2+y^2+4x-4y+4=0` which makes equal intercepts on the positive coordinates axes.

A

`x+y=2`

B

`x+y=2sqrt2`

C

`x+y=4`

D

`x+y=8`

Text Solution

Verified by Experts

The correct Answer is:
B
Let the equations of the required tangent be `x+y=a`, then length of the perpendicular from centre = radius
`therefore" "|(-2+2-a)/(sqrt2)|=2 rArr a=2sqrt2," "(because, a gt 0)`. Hence, the equation of tangent is `x+y=2sqrt2`
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