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The equation of the diameter of the ...

The equation of the diameter of the circle `x^(2) + y^(2) - 6x + 2y = 0 ` which passes through origin is

A

`x+3y=0`

B

`x-3y=0`

C

`3x+y=0`

D

`3x-y=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Diameter of `(x-3)^(2)+(y+1)^(2)=10` passes through centre i.e (3,-1) & also passes through (0,0) `implies` Line is `(y-0)/(x-0)=(-1-0)/(3-0)impliesx+3y=0`
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