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Three charges are placed at the vertices...

Three charges are placed at the vertices of an equilateral triangle of side 'a' as shown in the following figure. The force experienced by the charge placed at the vertex. A in a direction normal to BC is

A

`(Q^(2))/(4pi in_(0)a^(2))`

B

`-(Q^(2))/(4pi in_(0) a^(2))`

C

zero

D

`(Q^(2))/(2pi in_(0)a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`F_(R )=2F cos theta//2 `
`=2F cos 120//2=2F cos 60`
`=F= (kQ^(2))/(a^(2))= (Q^(2))/(4pi epsilon_(0)a^(2))`

However, this force is the resultant force parallel to BC.
`:.` Force perpendicular to BC is zero.
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