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Calculate the tension in the thread duri...

Calculate the tension in the thread during equilibrium condition(`m=80×10^(-6)`kg, q=`2×10^(-8)`C) -

A

8.8 N

B

`8.8 xx 10^(2)N`

C

`8.8 xx 10^(-4)N`

D

`8.8 xx 10^(-3)N`

Text Solution

Verified by Experts

The correct Answer is:
C

during equilibrium
`T cos theta = mg`
`T sin theta = qE`
`T = sqrt((mg)^(2)+(qE)^(2))`
`T= sqrt((80xx10xx10^(-6))^(2)+(2xx10^(-8) xx 2 xx 10^(4))^(2))`
`T= sqrt(64 xx 10^(-8) +16 xx 10^(-8))`
`T= sqrt(80 xx 10^(-8)) = 8.8 xx 10^(-4)N`
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