On moving a charge of 2C from a point A where potential is +12V to a point B where potential is -12 V, the work done is -

Options

A. `+24J`
B. `-24J`
C. 48 J
D. `-48J`

Explanation

To solve the problem of calculating the work done when moving a charge from one point to another with different electric potentials, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Work Done**:
Work done (W) in moving a charge (q) through a potential difference (V) is given by the formula:
\[ W = V \times q \]
where V is the potential difference between the two points.

2. **Identify the Initial and Final Potentials**:
- The potential at point A (initial potential, \( V_i \)) is +12 V.
- The potential at point B (final potential, \( V_f \)) is -12 V.

3. **Calculate the Potential Difference**:
The potential difference (V) is calculated as:
\[ V = V_f - V_i \]
Substituting the values:
\[ V = (-12 \, \text{V}) - (+12 \, \text{V}) = -12 \, \text{V} - 12 \, \text{V} = -24 \, \text{V} \]

4. **Substitute the Charge Value**:
The charge (q) being moved is given as 2 C.

5. **Calculate the Work Done**:
Now, substitute the values into the work done formula:
\[ W = V \times q = (-24 \, \text{V}) \times (2 \, \text{C}) = -48 \, \text{J} \]

6. **Conclusion**:
The work done in moving the charge from point A to point B is:
\[ W = -48 \, \text{J} \]

### Final Answer:
The work done is -48 Joules.

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