In a series `LCR` circuit, at the frequencies `f_(1)` and `f_(2)` of `AC` source, the current amplitude falls to `(1)/(sqrt(2))` of the current amplitude at resonance. Then the value of `f_(2) - f_(1)` is

In a series LCR circuit, the frequencies at which the current amplitude is (1)/(sqrt(2)) mes the current amplitude at resonance are f_(1) and f_(2) (gt f_(1)). Find the frequency bandwidth of resonance which is defined as Deltaf=f_(2)-f_(1). Express your answer in terms of R and L. Assume that resonance frequency f_(0)gtgtDeltaf

In a series LCR circuit, impedance Z is same at two frequencies f_1 and f_2 . Therefore, the resonant frequency of this circuit is

At resonant frequency the current amplitude in series LCR circuit is

At resonant frequency the current amplitude in series LCR circuit is

In the given figure , a series L-C-R circuit is connected to a variable frequency source of 230 V . The impedance and amplitude of the current at the resonating frequency will be

In the given figure , a series L-C-R circuit is connected to a variable frequency source of 230 V . The impedance and amplitude of the current at the resonating frequency will be

In LCR series drcuit, at resonance the applied e.m.f. and current