If `A+B+C=pi\ &sin(A+C/2)=ksinC/2, t h e ntanA/2tanB/2=` a.`(k-1)/(k+1)` b. `(k+1)/(k-1)` c.`k/(k+1)` d. `(k+1)/k`

If A+B+C=pi&sin(A+(C)/(2))=k(sin C)/(2), then (tan A)/(2)(tan B)/(2)= a.(k-1)/(k+1) b.(k+1)/(k-1) c.(k)/(k+1) d.(k+1)/(k)

If s e ctheta+t a ntheta=k ,\ costheta= a. (k^2+1)/(2k) b. (2k)/(k^2+1) c. k/(k^2+1) d. k/(k^2-1)

A+ B = C and tan A = k tan B , then prove that sin (A-B) = (k-1)/(k+1) sin C

A+B=C and tan A=k tan B, then prove that sin(A-B)=(k-1)/(k+1)sin C

If t a ntheta_1t a ntheta_2=k , then ("cos"(theta_1-theta_2))/("cos"(theta_1+theta_2))= a. (1+k)/(1-k) b. (1-k)/(1+k) c. (k+1)/(k-1) d. (k-1)/(k+1)

If sec theta+tan theta=k,cos theta=(k^(2)+1)/(2k)b(2k)/(k^(2)+1)c*(k)/(k^(2)+1)d*(k)/(k^(2)-1)

If tan theta_(1)tan theta_(2)=k, then (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=(1+k)/(1-k) b.(1-k)/(1+k) c.(k+1)/(k-1) d.(k-1)/(k+1)

If k in R_ot h e ndet{a d j(k I_n)} is equal to K^(n-1) b. K^(n(n-1)) c. K^n d. k

Two consecutive irreversible fierst order reactions can be represented by Aoverset(k_(1))(rarr)Boverset(k_(2))(rarr)C The rate equation for A is readily interated to obtain [A]_(t)=[A]_(0).e^(-k_(1^(t))) , and [B]_(t)=(k_(1)[A]_(0))/(k_(2)-k_(1))[e^(-k_(1)(t))-e^(-k_(2)(t))] At what time will B be present in maximum concentration ? a) (K_(1))/(K_(2)-K_(1)) b) (1)/(k_(1)-k_(2) In (k_(1))/(k_(2)) c) (1)/(k_(2)-k_(1)) In (k_(1))/(k_(2)) d) none of these

If an angle alpha is divided into two parts A&B such that A-B=x and tan A:tan B=k:1 Then the value of sin x is (A) (k+1)/(k-1)sin alpha (k)/(k+1)sin alpha (C) (k-1)/(k+1)sin alpha (D) tan alpha