In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to `(3)/(4)`th of the original length and the tension is changed. The factor by which the tenstion is to be changed is

Find the fundamental note emitted by a string of length 10sqrt(10) cm under tension of 3.14 kg. Radius of string is 0.55 mm and density =9.8gcm^(-3) .

Determing in what way and how many times will the fundamental tone frequency of a stretched wire change it its length is shortened by 35 % and the tension increased by 70% .

The frequency of transverse vibration on a stretched string is 150 Hz. If the tension is increases four times and length is reduced to one fourth of its original value, the frequency of vibration will be

In a stretched string under tension and fixed at both ends, the tension is increased by four times, and the length is doubled, the frequency

The frequency of fundamental mode of vibration of a stretched string fixed at both the ends is 25 Hz. If the string is made to vibrate with 7 nodes , what is the frequency of vibration ? If the length of string is 3 m , what is the frequency of the 4th harmonic ?

A middle C string on a piano has a fundamental frequency of 262 Hz , and the A note has fundamental frequency of 440 Hz . (a) Calculate the frequencies of the next two harmonics of the C string. (b) If the strings for the A and C notes are assumed to have the same mass per unit length and the same length, determine the ratio of tension in the two strings.