`(x+1)/(x-7)geq2`

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(x+1)/(x-7)>=2

If (|x-2|)/(x-2)geq0, then x in [2,oo) b. x in (2,oo) c. x in (-oo,2) d. x in (-oo,2]

Show that the function defined by f(x)=(3-2x), x lt2 and f(x)=3x-7, x geq 2 is not derivable at x=2

2(x-4)/((x-1)(x-7))>=(1)/(x-2)

If x=(1)/(2)(sqrt(7)+(1)/(sqrt(7))) ,then , log_(27)((sqrt(x^(2)-1))/(x-sqrt(x^(2)-1))) is equal to

(x^(2))/((x+1)^(2))+((x+1)^(2))/(x^(2))-(x)/(x+1)+(x+1)/(x)-(7)/(4)=p^(2)

(x^(2))/(x+1)+((x+1)^(2))/(x^(2))-(x)/(x+2)+(x+1)/(x)-(7)/(4)=p^(2)

Solve for x: (x+3)/7+(x-1)/2=2x