`A,B ,C` are three persons among `7` persons who speak at a function.The number of ways in which it can be done if `A` speaks before `B` and `B` speaks before `C` is

A, B, C are three persons among 7 persons who speak at a function. The number of waysin which it can be done if 'A' speaks before 'B' and 'B' speaks before 'C' is

Among 10 persons,A,B,C are to speak at a function.The number of ways in which it can be done if A wants to speak before B and B wants to speak before C is a.10!/24b.9!/6c10!/6d d.none of these

Ten persons, amongst whom are A, B and C are to speak at function. Find number of ways in which it can be done if A wants to speak before B, and B wants to speak before C ?

Three persons A,B and C speak at a function along with 5 other persons.If the persons speak at random,find the probability that A speaks before B and B speaks before C

There are 5 speakers A,B,C,D and E. The number of ways in which A will speak always before B is:

Seven different lecturers are to deliver lectures in seven perday.A,B and C are three oftne lectures.The number of ways in which a routine for theday canr be made such that A delivers his lecture before B and B before C, is