A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is 10 ms^-1 , then the maximum height attained by the stone is ( g= 10 ms^(-2) )

A particle is thrown vertically upwards. If its velocity is half of the maximum height is 20 m//s , then maximum height attained by it is

A stone thrown vertically upwards takes 3 s to attain maximum height. Find the (i) initial velocity of the stone (ii) maximum height attained by the stone (g = 9.8 m s^(-2))

A rocket is projected vertically upwards and its time velocity graph is shown in the figure-1.115. The maximum height attained by the rocket is :

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

From an elevated point A, a stone is projected vertically upwards. When the stone reaches a distance h below A, its velocity is doubleof what it was at a height h above A. Show that the greatest height attained by the stone is 5/3 h.

A body of mass 4kg is projected vertically up with a velocity of 20ms^(-1) . If the energy spent in overcoming air resistance is 200J ,the maximum height attained by it is? (g=10m/ s^(2) )