If at t=0,u=2ms^(-1) find out it maximum velocity Since whole motion is accelerating.Therefore velocity will be max at the end , of the motion which will be

If displacement x= t^(4) , then the ratio of acceleration and velocity of motion will be

A particle is executing a simple harmonic motion its maximum acceleration is a and maximum velocity is beta .Then its time of vibration will be

At the start of a motion along a line the initial velocity is u and acceleration is at. The final velocity vafter time t, is

The maximum acceleration of a simple harmonic motion is a and the maximum velocity is beta .The frequency of the SHM is given by the expression...

A particle is executing a simple harmonic motion. Its maximum acceleration is alpha and maximum velocity is beta . Then, its time period of vibration will be

The velocity of a particle moving in a straight line varies with time in such a manner that v versus t graph is represented by one-half of an ellipse. The maximum velocity is v_m and the total time of motion is t_0 (i) average velocity of the particle is (pi)/(4) v_m (ii) such motion cannot be realized in practical terms.

A 0.5 kg body performs simple harmonic motion with a frequency of 2 Hz and an amplitude of 8 mm . Find the maximum velocity of the body, its maximum acceleration and the maximum restoring force to which the body is subjected.

A particle moves in a straight line with constant velocity of 5 ms^(-1) for 2 sec. it then moves with a constant acceleration of -2ms^(-2) for 8 sec. draw velocity-time graph for 10 sec of motion and find (a). Final velocity (b). Displacement (c). Total distance.