Prot that the equation `k cos x-3s in x=k+1` possess a solution if `k in (-oo,4]dot`

prove that the equation k cos x-3sin x=k+1 has a solution for x' for k in(-oo,4]

If the equation k cos x-3sin x=k+1 has a solution for x then

The equation k cos x-3sinx=k+1 is solvable only if

The equation K-sin theta+cos2 theta=2k-7 possesses a real solution if

The values of k for which the equation sin^(4)x+cos^(4)x+sin2x+k=0 possess solution (A)k in[-(3)/(2),1] (B) k in[0,(1)/(2)] (C) k in[-(3)/(2),(1)/(2)] (D) k in[(1)/(2),1]

" If the equation "2ksinx+7=4k" - cos "2x" possesses a solution for "k in[a,b]" ,then "(a+b)" is equal to "

If the equation 2ksinx+7=4k-cos2x possesses a solution for k in[a,b] ,then (a+b) is equal to

The number of integral values of k for which the equation 7cos x+5sin x=2k+1 has a solution is (1)4(2)8(3)10(4)12