An electron in the beam of a TV picture tube is accelerated by a potential difference of `2.00 kV`. Then, it passes through region of transverse magnetic field, where it moves in a circular arc with radius `0.180 m`. what is the magnitude of the field?

An electron in the beam of a TV picture tube is accelerated by a potential difference of 2.00 kV . Then, it passes through region of transverse magnetic field, where it moves in a circular arc with radius 0.180 m . at is the magnitude of the field?

A particle of mass m carrying charge q is accelerated by a potential difference V. It enters perpendicularly in a region of uniform magnetic field B and executes circular arc of radius R, then q/m equals

A charge q is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field , where it moves in a circle of radius r . The potential difference required to move it in a circle of radius 2 r is

A beam of electrons is accelerated through a potential difference V . It is then passed normally through a uniform magnetic field where it moves in a circle of radius r . It would have moved in a circle of radius 2r if it were initially accelarated through a potential difference

An electron of mass 'm' is accelerated through a potential difference of V and then it enters a magnetic field of induction B . Normal to the lines of force. Then the radius of the circular path is

Assertion : An electron and a proton are accelerated by same potential difference and then enter in uniform transverse magnetic field. The radii of the two will be different. Reason : Charges on them are different.