Two spheres A and B of radius a and b respectively are at the same potential. The ratio of the surface charge density of A to B is

Two spheres A and B of radius 'a' and 'b' respectively are at same electric potential. The ratio of the surface charge densities of A and B is

Two spheres of radius a and b respectively are charged and joined by a wire. The ratio of electric field of the spheres is

two metal spheres of radii R_(1) and R_(2) are charged to the same potential. The ratio of charges on the spheres is

Two charged spherical conductors of radius R_1 and R_2 are connected by a wire. Then the ratio of surface charge densities of the spheres (sigma_1)/(sigma_2) is

Two conducting concentric, hollow spheres A and B have radii a and b respectively, with A inside B. Their common potentials is V. A is now given some charge such that its potential becomes zero. The potential of B will now be

Spheres A and B have their radii 40 cm and 10 cm respectively. Ratio of surface area of A to the surface area of B is :

A number of spherical conductors of different radii are charged to same potential. The surface charge density of each conductor is related with its radius as

Two copper spheres A and B of same radii, one hollow and the other solid are charged to the same potential. Which of the two will hold more charge

The answer to each of the following questions is a single-digit integer ranging from 0 to 9. Darken the correct digit. There are two metallic spheres A and B of radii R and 3R respectively. Both the spheres are given charge so that they may attain the same potential. If E_(A) is the electric field on the surface of sphere A and E_(B) is the electric field intensity on the surface of sphere B then calculate E_(A)//E_(B) .