If `x^(2)+ax+b=0` and `x^(2)+bx+a=0,(a ne b)` have a common root, then `a+b` is equal to

If the quadratic equation x^(2) +ax +b =0 and x^(2) +bx +a =0 (a ne b) have a common root, the find the numeical value of a +b.

If x^(2)+ax+bc=0 and x^(2)+bx+ca=0 have a common root,then a+b+c=1

Ifc^(2)=4d and the two equations x^(2)-ax+b=0 and x^(2)-cx+d=0 have a common root,then the value of 2(b+d) is equal to 0 ,have one

If x^(2)+ax+b=0 and x^(2)+bx+ca=0(a!=b) have a common root,then prove that their other roots satisfy the equation x^(2)+cx+ab=0

If x^(2)+ax+10=0 and x^(2)+bx-10=0 have common root,then a^(2)-b^(2) is equal to 10 (b) 20(c)30 (d) 40

If ax^(2) + 2bx + c = 0 and ax^(2) + 2cx + b = 0, b ne c have a common root, then (a + b + c)/( a) is equal to