The director circle of a hyperbola is `x^(2) + y^(2) - 4y =0`. One end of the major axis is (2,0) then a focus is

The Equation of director circle of x^(2)+y^(2)+6x+2y+1=0 is

If the foci of (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 coincide with the foci of (x^(2))/(25)+(y^(2))/(9)=1 and the eccentricity of the hyperbola is 2, then a^(2)+b^(2)=16 there is no director circle to the hyperbola the center of the director circle is (0,0). the length of latus rectum of the hyperbola is 12

The area of the portion of the circle x^(2)+y^(2)-4y=0 lying below the x -axis is

The equation of the director circle of the hyperbola (x^2)/(16)-(y^2)/(4) = 1 is given by :

The transverse axis of the hyperbola 5x^2-4y^2-30x-8y+121=0 is

A circle x^(2)+y^(2)+4x-2sqrt(2)y+c=0 is the director circle of the circle S_(1) and S_(1) is the director circle of circle S_(2), and so on.If the sum of radii of all these circles is 2 ,then the value of c is k sqrt(2), where the value of k is

Equation of the circle concentric with x^(2)+y^(2)-8x-16y+4=0 and touches y- axis is