A block of mass m slides down an inclined plane of inclination `theta` with uniform speed The coefficient of friction between the block and the plane is `mu`. The contact force between the block and the plane is .

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

A block of mass m slides down a rough inclined plane of inclination theta with horizontal with zero initial velocity. The coefficient of friction between the block and the plane is mu with theta gt tan^(-1)(mu) . Rate of work done by the force of friction at time t is

A block of 4 kg slides down an inclined plane which makes an angle theta = 60^(@) with the horizontal. The co-effcient of friction between the block and the plane is mu = 3//4 . The force exerted by the block on the plane is (g = 10 m//s^(2))

A block of weight 1 N rests on a inclined plane of inclination theta with the horizontal. The coefficient of friction between the block and the inclined plane is mu . The minimum force that has to be applied parallel to the inclined plane to make the body just move up the plane is

A block of mass m is placed at rest on an inclination theta to the horizontal.If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is