In a right angled triangle ABC. the hypotenuse AB=p, then AB.AC+BC.BA+CA.CB

In a right angled triangle ABC, the hypotenuse AB =p, then vec(AB).vec(AC) + vec(BC).vec(BA)+vec(CA).vec(CB) is equal to:

If in a right-angled triangle ABC, the hypotenuse AB=p, then vec AB.AC+vec BC*vec BA+vec CA.vec CB is equal to 2p^(2) b.(p^(2))/(2) c.p^(2) d.none of these

In a right angled triangle hypotenuse AC= p, then vec(AB). vec(AC ) + vec(BC) .vec(BA) + vec(CA). vec(CB) equal to ?

If in a right-angled triangle ABC, hypotenuse AC=p, then what is vec(AB).vec(AC)+vec(BC).vec(BA)+vec(CA).vec(CB) equal to ?

1.In a right angled triangle ABC,AB=AC Thena:b: c is

Suppose ABC is a right angled triangle with angleC=pi//2 . If abs(AB)=5," then "AB*AC+BC*BA+CA*CB= ________

In a right angled triangle ABC,D is the foot of the perpendicular from B on the hypotenuse AC . If AB=3cm and BC=4cm, what is the area of /_\ABD

In a right-angled triangle,the square of hypotenuse is equal to the sum of the squares of the two sides.Given that /_B of /_ABC is an acute angle and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

In a right -angled triangle ABC, right-angled at B, if AB=2sqrt6 and AC-BC=2 , then find sec A+ tan A .

In a right-angled triangle ABC , D is the foot of the perpendicular from B on the hypotenuse AC . If AB=3cm and BC=4cm, what is the area of /_\ABD?