Suppose that the position function for a particle is given as ⃗ r(t)=x(t)ˆi+y(t)ˆj with x(t)=t+1 and y(t)=(t^(2)/8)+1) The ratio of magnitude of average velocity (during time interval t=2 to 4sec) to the speed at t=2sec is

Suppose that the position function for a particle is given as vec( r ) ( t) = x ( t) hat( i) + y (t) hat(j) with x ( t) = t+1 and y ( t) = ( t^(2) //8) + 1 . The ratio of magnitude of average velocity ( during time interval t = 2 to 4 sec) to the speed at t =2 sec is

Position of a particle at any instant is given by x = 3t^(2)+1 , where x is in m and t in sec. Its average velocity in the time interval t = 2 sec to t = 3 sec will be :

The intantaneous coordinates of a particle are x= (8t-1)m and y=(4t^(2))m . Calculate (i) the average velocity of the particle during time interval from t =2s to t=4s (ii) the instantaneous velocity of the particle at t = 2s .

The distance travelled by a body and the time t are related by x=4-3t+2t^(2)m .The average velocity in a time interval of 1 to 4 sec is m/s

A particle's position as a function of time is described as y (t) = 2t^(2) + 3t + 4 . What is the average velocity of the particle from t = 0 to t = 3 sec ?

The displacement of a particla moving in straight line is given by s=t^(4)+2t^(3)+3t^(2)+4 , where s is in meters and t is in seconds. Find the (a) velocity at t=1 s , (b) acceleration at t=2 s , (c ) average velocity during time interval t=0 to t=2 s and (d) average acceleration during time interval t=0 to t=1 s .

A particle is projected with speed u at angle theta with horizontal from ground . If it is at same height from ground at time t_(1) and t_(2) , then its average velocity in time interval t_(1) to t_(2) is

The co-ordinate of the particle in x-y plane are given as x=2+2t+4t^(2) and y=4t+8t^(2) :- The motion of the particle is :-