Each pole of magnet of length 20 cm in a magnetic field of induction 0.2 T experiences a force 20 N. The magnetic moment of magnet is

A short bar magnet placed with its axis at 30^@ to a uniform magnetic field of 0*2T experiences a torque of 0*06N-m . Calculate magnetic moment of the magnet. What orientation of magnet corresponds to its stable equilibrium in the magnetic field?

If the maximum couple acting on a magnet in a field of induction 0.2 tesla is 10 Nm , what is its magnetic moment?

A very small magnet is placed in the magnetic meridian with its south pole pointing north. The null point is obtained 20 cm away from the centre of the magnet. If the earth's magnetic field (horizontal component) at this point be 0.3 Gauss, the magnetic moment of the magnet is

A bar magnet of magnetic moment 0.4 Am^(2) is placed in a uniform magnetic field of induction 5 xx10^(-2) tesla. The angle between the magnetic induction and the magnetic moment is 30^(@) . The torque acting on the magnet is

When a bar magnet of magnetic moment barM is placed in a magnetic field of induction field strength barB , each pole experiences a force of barF then the distance between the south and north pole of the magnet measured inside it is