If `a(5+q^(2))+2bq+c=0` and `a(5+r^(2))+2br+c=0` where `a!=0` then `q+r=`

If a(p+q)^2+2bpq+c=0 and q(p+r)^2+2bpr+c=0 then (A) qr=p^2 + c/a (B) qr=p^2 - c/a (C) q+r = 2(a+b)/a (D) q+r= -2(a+b)/(a)

2r^(2)-5r+2=0

Prove that equations (q-r)x^(2)+(r-p)x+p-q=0 and (r-p)x^(2)+(p-q)x+q-r=0 have a common root.

If the equations px^2+2qx+r=0 and px^2+2rx+q=0 have a common root then p+q+4r=