An oil drop having a mass `4.8xx10^(-10)`g. and charge `2.4xx10^(-18)`C stand still between two charged horizontal plates seperated by a distance of `1cm`. If now the polarity of the plates is changed the instantaneous acceleration of the drop is `("in" ms^(2)),(g=10ms^(-2))`

In a millikon's oil drop experiment, an oil drop of mass 0.64xx10^(-14)kg , carrying a charge 1.6xx10^(-19)C remain stationary between two plates seperated by a distance of 5mm . Given g=9.8m//s^(2) , the voltage that must be applied between the plates being

A charged drop of mass 3.2 xx 10^(-12) g floats between two horizontal parallel plates maintained at potential difference of 980 V and separation between the plates is 2 cm. The number of excess or deficient electrons on the drop is

An oil drop of mass 5xx10^(-15) kg carries a charge Q. The drop is stationary between two parallel metal plates 25 mm apart with a p.d. of 1000 V between them. Determine Q. Take g=10 ms^(-2) .

A Water of mass 3.2xx10^(-18)kg and carrying a charge of 1.6xx10^(-19)C is suspended stationary betwaeen two plates of an electric field. Given g=10 m//s^(2) , the intensity of the electric field required is

A positively charged oil droplet remins stationary in the electric field between two horizontal plates separated by a distance of 1 cm . The charge on the drop is 10^(-15) C and mass of the droplet is 10^(-11) g , the potential difference between the plates and if the polarity is reversed , the instantaneous of the droplet are

A rocket has an initial mass of 20xx10^(3) kg. If it is to blast off with an initial acceleration of 4ms^(-2) , the initial thrust needed is (g~=10ms^(-2))

An oil drop has 6.39 xx 10^(-19)C charge .How many electrons does this oil drop has ?

An oil drop with charge 1.6xx10^(-18)C is balanced in air between two metallic plates 10 mm apart. Calculate the voltage required between the plates if mass of the drop is 2.4xx10^(-14)kg .