The momenta of a body in two perpendicular directions at any time 't' are given by `P_(x)=2t^(2) +6` and `P_(y)=(3t^(2))/(2)+3`. The force acting on the body at `t =2` sec is .

The angular momentum of a body is given by L= (4t^(2)+2t+7)kgm^(2)s^(-1) .The net torque acting on the body at t=2s is

A body of mass 1kg is moving according to the law x(t)=(5t+4t^(2)+6t^(3))m . The force acting on the body at time t=2s is

The mass of a body is 2.5 Kg. it is in motion and its velocity upsilon after time t is upsilon = (t^3)/(3) +(t^2)/(2) +1 Calculate the force acting on the body at the time t =3 s.

The coordinates of a moving particle at any time t are given by, x = 2t^(3) and y = 3t^(3) . Acceleration of the particle is given by

The angular displacement at any time t is given by theta(t) = 2t^(3)-6^(2) . The torque on the wheel will be zero at

A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + rt^(3) where , q = 4 ms^(-2) , p = 3 ms^(-1) and r = 5 ms^(-3) . The force acting on the body at t = 2s is

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

Two wave function in a medium along x direction are given by y_(1)=1/(2+(2x-3t)^(2))m , y_(2)=-1/(2+(2x+3t-6)^(2))m Where x is in meters and t is in seconds

Momentum of a body moving in a straight line is p = (2t^3 + t^2 + 2t + 1) kg m/s. Force acting on a body at t = 2 sec.

The position of a particle moving in the x-y plane at any time t is given by , x=(3t^2-6t) metres, y =(t^2-2t) metres. Select the correct statement.