If f(u) ` = 1/(u^(2)+u-2)` , where `u = 1/(x-1)` , then the points of discontinuity of f are x = …..

If y = (u -1)/(u + 1) and u = sqrt(x) , then (dy)/(dx) is

Match the following for the type of discontinuity at x=1 in column II for the function in column I. f(x)=1/(x-1) , p. Removable discontinuity f(x)=(x^3-x)/(x^2-1) , q. Non-removable discontinuity f(x)=(|x-1|)/(x-1) , r. Jump of discontinuity f(x)=sin(1/(x-1)) , s. Discontinuity due to vertical asymptote , t. Missing point discontinuity , u. Oscillating discontinuity

int (du) / (u sqrt (u ^ (2) -1))

Find the points of discontinuity of y = (1)/(u^(2) + u -2) , where u = (1)/(x -1)

If x=sqrt (1+u^(2)),y =log (1+u^(2) ) ,then (dy)/(dx) =

the abscissae of any two points on the parabola y^(2)=4ax are in the ratio u:1. prove that the locus of the point of intersection of tangents at these points is y^(2)=(u^((1)/(4))+u^(-((1)/(4))))^(2)ax

Find the point of discontinuity of y=f(u) where f(u)=(3)/(2u^(2)+5u-3) and u=(1)/(x+2)