Two organ pipe , both closed at one end , have lengths `l and l + Delta l`. Neglect end corrections. If the velocity of sound in air is `V`, then the number of beats//s` is

In closed organ pipe at one end-

The sequence of harmonics of a pipe open at one end and closed to the other end are 250Hz and 350Hz . If the velocity of sound in air is 340m/s, then the resonating length of the air column in its fundamental mode will be

A narrow pipe of length 2m is closed at one end. The velocity of sound in air is 320 m/s. Neglecting end corrections , the air column in the pipe will resonate for sound of frequencies :

If the two tubes of lengths 50cm and 51cm closed at one end produce 7 beats in two second, when sounded to their fundamental notes neglecting end correction , then velocity of sound in air will be

A string of length 50 cm and mass 12.5 g is fixed at both ends. A pipe closed at one end has a length 85 cm . When the string vibrates in its second overtone and the air column in the pipe in its first. Overtone, they produce a beats frquency of 6 Hz . It is also observed that decreasing teh tension in the string decreaes beats frequency. Neglect the end correction in the pipe and velocity of sound in air is 340 m//s . then the tension in the string is

Velocity of sound in air is 320 m s^(–1) . A pipe closed at one end has a length of 1 m. Neglecting end correction, the air column in the pipe cannot resonate with sound of frequency

When a closed organ pipe of length l if the velocity of sound is v then the fundamental frequency will be

Two closed organ pipes have lengths L and L+X . When two pipes are sounded together , the beat frequency is

An open organ pipe has a length /and diameter d . If the velocity of sound in air is v, what is the fundamnetal frequency of the pipe when the end correction is spplied ?