A magnetic needle of pole strength `'m'` is privoted at its centre. Its `N-`pole is pulled eastward by a string. Then the horizontal force required to produce a deflection of `theta` from magnetic meridian `(B_(H) "horizontal componet of earths magnetic field")`

What is the value of the horizontal component of the earth's magnetic field at the poles?

A magnetic dipole of magnetic moment 6Am^(2) is lying in a horizontal plane with its north pole pointing toward 60^(@) East of North. Find the net horizontal magnetic field at a point· on the axis of the magnet 0.2m away from it. Horizontal Component of earth field at this place is 30 mu T .

A 30 cm long bar magnet is placed in the magnetic meridian with its north pole pointing south. The neutral point is obtained at a distance of 40 cm from the centre of the magnet. Pole strength of the magnet is (The horizontal component of earth’s magnetic field is 0.34 Gauss)

A short bar magnet with its north pole facing north forms a neutral point at P in the horizontal plane. If the magnet is rotated by 90^(@) in the horizontal plane, the net magnetic induction at P is (Horizontal component of earth's magnetic field =B_(H))

A magnetic needle of length 10cm, suspended at its middle point through a thread, stays at a an angle of 45^@ with the horizontal. The horizontal component of the earth's magnetic field is 18 muT . (a) Find the vertical component of this field. (b) If the pole strength of the needle is 1.6 A-m , what vertical force should be applied to an end so as to keep it in horizontal position?

A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the centre of the magnet. Calculate the horizontal component of earth’s magnetic field.

A short bar magnet of magnetic moment 1.2Am^(2) is placed in the magnetic meridian with its south pole pointing the north. If a neutral point is found at a distance of 20cm from the centre of the magnet, the value of the horizontal component of the earth's magnetic field is

At the magnetic north pole of the earth, the value of horizontal component of earth's magnetic field and angle of dip are, respectively

A magnetic dipole of magnetic moment 1.44 A m^2 is placed horizontally with the north pole pointing towards north. Find the positon of the neutral point if the horizontal component of the earth's magnetic field is 18 muT .

A short bar magnet is placed in the magnetic meridian of the earth with its north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East-West line drawn through the mid point of the magnet. What is the magnetic moment of the magnet in Am^(2) ? (Given m=10^(-7) in SJ units and B_(H)= horizontal component of earth's magnetic field =3.6xx10^(-5) tesla)