A galvanometer of resistance `20Omega` is to be shunted so that only `1%` of the current passes through it. Shunt connected is `99//20Omega`

A galvanometer of resistance 100ohms is shunted so that only 1//11 of the main current flows through the galvanometer. The resistance of the shunt is

A galvanometer of resistance 20Omega is shunted by a 2 Omega resistor. What part of the main current flows through the galvanometer ?

A galvanometer of resistance 90 Omega is shunted by a resistance of 10 Omega . What fraction of main current passes through the shunt ?

If a shunt is to be applied to a galvanometer of resistance 50Omega so that only 5% of total current passes through the galvanometer. The resistance of shunt should be

A galvanomter of resistance 50Omega is shunted by a resistance of 5Omega . What fraction of the main current passes through the galvanometer? Through the shunt?

When a galvanometer of resistance G is shunted with a low resistance S, then the effective resistance R_(eff) of galvanometer becomes R_(eff)=(GS)/(G+S) If current is passed through such a galvanometer, then the major amount of current flows through shunt and the rest through galvanometer, i.e., the current divides itself in the inverse ratio of resistance. Read the above passage and answer the following questions: (i) Why is the resistance of shunted galvanometer lower than that of shunt? (ii) A galvanometer of resistance 30Omega is shunted by a resistance of 3Omega . What fraction of the main current passes (i) through the galvanometer and (ii) through the shunt? (iii) What are the basic values you learn from the above study?

A moving coild galvanometer of resistance 20 Omega gives a full scale deflection when a current of 1mA is passed through it. It is to be converted into an ammeter reading 20A. But the resistance of the only shunt available is 0.005Omega . What resistance should be connected in series with the galvanometer coil?

A moving coil galvanometer of resistance 20 Omega gives a full scale deflection when a current of 1mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the shunt of 0.005 Omega only is available. What resistance should be connected in series with the galvanometer coil?

A galvanometer has a resistance of 3663Omega . A shunt Sis connected across it such that (1/34) of the total current passes through the galvanometer. Then the value of the shunt is :