An electron and a proton enter a magnetic field with same velocity then the ratio of their acceleration is (A)`(m_(P))/(m_(e))`,(B) `sqrt((m_(P))/(m_(e)))` (C) `sqrt((m_(e))/(m_(P)))`, (n) `m_(e)`?

An electron of mass m_(e) and a proton of mass m_(p) are moving with the same speed. The ratio of their de-Broglie wavelength lamda_(e)//lamda_(p) is

An electron (e,m) and photon have same energy E. Then the ratio lambda_e : lambda_p is?

The constancy of e/m ratio for electron shows that

Proton and electron are moving along circular path with same speed. Find out ratioof debroglie wavelength that is (lambda_e)/(lambda_p) If m_p =1836 m_e

The acceleration due to gravity on the surface of earth is 9.8 ms^(-2) .Time period of a simple pendulum on earth and moon are 3.5 second and 8.4 second respectively. Find the acceleration due to gravity on the moon . Hint : T_(e) = 2pi sqrt((L)/(g_(e))) T_(m)= 2pi sqrt((L)/(g_(m))) (T_(e)^(2))/(T_(m)^(2))= (g_(m))/(g_(e)) g_(m) = (T_(e)^(2))/(T_(m)^(2))g_(e)

The (e)/(m) value of electron is

e//m ratio of proton is greater than that of electron

An electron having mass 'm' and kinetic energy E enter in uniform magnetic field B perpendicularly, then its frequency will be : -