If the displacement (x) and velocity (v) of a particle executing simple harmonic motion are related through the expression `4v^2=25-x^2`, then its time period is given by

The velocity of a particle executing simple harmonic motion is

If the displacement (x) and velocity (v) of a particle executing SHM are related through the expression 3v^(2)=30-x^(2) . If the time period of the particle is T=pisqrt(n) , then what is the value of n?

The phase of a particle executing simple harmonic motion is pi/2 when it has

The total energy of a particle executing simple garmonic motion is (x- displacement)

The displacement of a particle in simple harmonic motion in one time period is

If the displacement (y in m) and velocity (v in ms^(-1)) of a particle executing SHM are related by the equation 4v^(2)=16-y^(2) , then the path length of the motion and time period of oscillation respectively are

If the displacement x and velocity v of a aprticle executing SHM are related as 4v^(2) = 25 - x^(2) . Then its maximum displacement in metre (x, v are in SI ) is

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscilltes is

If x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T , then, which of the following does not change with time ?