Home
Class 11
PHYSICS
An electron of mass m(e ) initially at r...

An electron of mass `m_(e )` initially at rest moves through a certain distance in a uniform electric field in time `t_(1)`. A proton of mass `m_(p)` also initially at rest takes time `t_(2)` to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of `t_(2)//t_(1)` is nearly equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

An electron of mass M_e , initially at rest, moves through a certain distance in a uniform electric field in time t_1 . A proton of mass M_p also initially at rest, takes time t_2 to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t_2//t_1 is nearly equal to

An electron of mass m_e starts from rest, moves a certain distance in uniform field and takes time t_1 . A proton of mass m_p also starts from rest in the same field and covers the same distande in time t_2 ,then t_1//t_2 is equal to

An electron and a proton travel through equal distances in the same uniform electric field E. Compare their time of travel. (Neglect gravity)

An electron initially at rest falls a distance of 2 cm in a uniform electric field of magnitude 3 xx 10^(4) N C^(-1) . The time taken by the electron to fall to this distance is

An electron initially at rest falls a distance of 1.5 cm in a uniform electric field of magnitude 2 xx10^(4) N//C . The time taken by the electron to fall this distance is

A train is at rest. It accelerates for a time t_(1) at a uniform rate alpha and then comes to rest under a uniform retardation rate beta for time t_(2) . The ratio t_(1)//t_(2) is equal to

An electron of mass m and charge q is accelerated from rest in a uniform electric field of strength E. The velocity acquired by it as it travels a distance l is