A particle moves in a straight line with a constant acceleration.It changes its velocity from 10m/s to 20m/s while covering a distance of 135m in t second.What is the value of t?

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms^-1 to 20 ms^-1 while passing through a distance 135 m in t seconds. The value of t is.

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .

A particle moves in a straight line with constant acceleration If it covers 10 m in first second and 20 m in next second find its initial velocity.

A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes 20 m//s and in tenth second it travels a distance of 10 m . Then the acceleration of the particle will be.

A particle is moving in a straight line under constant acceleration of 4 m//s^(2) . If its velocity at t=0 is 10 m//s, the displacement of particle in the 5^(th) second of its motion is

A particle moves rectilinearly with a constant acceleration 1 m//s^2 . Its speed after 10 seconds is 5 m//s . The distance covered by the particle in this duration is.

A particle moves in a straight line with an acceleration a m/s^(2) at time t seconds,where a=-(1)/(t^(2)) .When t=1 the particle has a velocity of 3m/s .If the velocity of the particle at t=4s is (9)/(n)ms^(-1) The value of n is

A particle moves in straight line in same direction for 20 seconds with velocity 3 m//s and the moves with velocity 4 m//s for another 20 sec and finally moves with velocity 5 m//s for next 20 seconds. What is the average velocity of the particle?