If the roots of the equation `x^2-bx+c=0` are two consecutive integers then `3(b^2-4c)=`

If the roots of the equation x^(2)-bx+c=0 are two consecutive integers,then find the value of b^(2)-4c.

If the roots of x^(2)-bx+c=0 are two consecutive integers then b^(2)-4c=

If the roots of x^(2)-bx+c=0 are two consecutive integers,then b^(2)-4c is 0(b)1 (c) 2 (d) none of these

If a+b+c=0 then roots of the equation 3ax^(2)+4bx+5c=0 are

If all the roots of the equation x^(3)+ax^(2)+bx+c=0 are positive integers greater than 2 and a+b+c=-46 then a=-14