A closest distance of approach of an "alpha" particle travelling with a velocity "v towards "Al(13)" nucleus is d The closest distance of approach of an alpha particle travelling with velocity 4V towards Fe(26) nucleus is

A closest distance of approach of an a particle travelling with a velocity V towards Al_(13) nucleus . d . The closest distacne of approach of an alpha particle travelling with velocity 4V toward Fr_(26) nucleus is

The closed distance of approach of an alpha- particle travelling with velocity V towards a stationary nucleus is d .For the closest distance to become (d)/(3) towards a stationary nucleus of double of the charge,the velocity of projection of the alpha- particle has to be

Write the expression for distance of closest approach for a alpha -particle.

The distance oif closest approach of an alpha-particle fired towards a nucleus with momentum p is r. What will be the distance of closest approach when the momentum of alpha-particle is 2p ?

Calculate the nearest distance of approach of an alpha -particle of energy 2.5 Me V being scattered by a gold nucleus (Z=79).

The distance of closest approach of an alpha -particle fired at nucleus with momentum p is d. The distence of closest approach when the alpha -particle is fired at same nucleus with momentum 3p will be

When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as