A body is thrown vertically upwards from the ground. It reaches a maximum height of `20 m` in `5s`. After what time it will reach the ground from its maximum height position ?

A body is thrown vertically up from the ground. It reaches a maximum height of 100 m in 5 sec . After what time it will reach the ground from the maximum height position

A stone is thrown vertically up from the ground. It reaches a maximum height of 50 m in 10 sec. After what time it will reach the ground from maximum height position ?

A stone is projected vertically from the ground.It reaches the maximum height of 500m in 10 sec.After what time it will reach the ground from the maximum height reached?

A stone thrown vertically up from the ground reaches a maximum height of 50 m in 10s. Time taken by the stone to reach the ground from maximum height is

A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance travelled by the body will be same in :-

A stone projected vertically upwards from the ground reaches a maximum height h . When it is at a height (3h)//(4) , the ratio of its kinetic and potential energies is

A body is thrown vertically up to reach its maximum height in t seconds. The total time from the time of projection to reach a point at half of its maximum height while returning (in seconds) is

A body is thrown vertically up to reach its maximum height in t seconds. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is:

A body is thrown vertically upward from a point A 125 m above the ground. It goes up to a maximum height of 250 m above the ground and passes through A on its downward journey. The velocity of the body when it is at a height of 70 m above the ground is (g=10 m//s^(2))

A body thrown vertically upwards reaches a maximum height h . It then returns to ground . Calculate the distance travelled and the dispacement .