A proton enters a magnetic field of strength `10^(-3)T` along north with a speed of `10^(6)ms^(-1)` along east.Find the direction and magnitude of the acceleration of the particle in `10^(11)m/sec^(2)`?

A proton enters a magnetic field of flux density 2*5T with a speed of 1*5xx10^7ms^-1 at an angle of 30^@ with the field, Find the force on the proton.

A particle is moving at uniform speed 2 ms^(-1) along a circle of radius 0.5m .The centripetal acceleration of particle is

A beam of protons enters a uniform magnetic field of 0.3T with velocity of 4xx10^5m//s in a direction making an angle of 60^(@) with the direction of magnetic field. The path of motion of the particle will be

A proton is moving with a velocity of 5 xx 10^(5) m//s along the Y-direction. It is acted upon by an electric field of intensity 10^(5) V/m along the X-direction and a magnetic field of 1 Wb//m^(2) along the Z-direction. Then the Lorentz force on the particle is :

A proton enter in a uniform magnetic field of 2.0 mT at an angle of 60degrees with the magnetic field with speed 10m/s. Find the picth of path

A proton (mass = 1.6times10^(-27)Kg enters into a magnetic field of induction 3T with a velocity of 10^(7)ms^(-1) at 30 to the field.The force on the proton?

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A proton enters a magnetic field with a velocity of 2.5 xx10^(7)ms^(-1) making an angle 30^(@) with the magnetic field. The force on the proton is (B=25T)